Entry tags:
"Functional Collection Programming with Semi-Ring Dictionaries"
arxiv.org/abs/2103.06376
page 2: "Semi-ring dictionaries realize the well-known connection between relations and tensors" (from "In-Database Learning with Sparse Tensors" 2016-2018 paper)
page 2: "Semi-ring dictionaries realize the well-known connection between relations and tensors" (from "In-Database Learning with Sparse Tensors" 2016-2018 paper)
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Multiplication is defined in a way that is not commutative by default, where multiplying a dictionary with a scalar results in each value of the dictionary being multiplied by the scalar
This phrase is confusing: it says that multiplication is not commutative by default (what does "default" mean here?) and then it talks about multiplying dictionaries by scalars as if to illustrate the non-commutativity.
To understand what this means, you need to actually look into the paper and find what is commutative and what is non-commutative.
A reasonable rewrite would be: "Multiplication by scalars is in general non-commutative. (full stop, it's going to be a different topic now!) Multiplying a dictionary with a scalar results in ..."
no subject
(Как и в том, что я пишу, особенно, если я решаю не исправлять, а оставляю, как получилось (это - некоторая особенность текущей парадигмы, что она может думать только вслух, а не про себя; это можно чинить, но до какой степени надо торопиться это чинить, это не очень понятно).)