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arxiv.org/abs/2103.06376
page 2: "Semi-ring dictionaries realize the well-known connection between relations and tensors" (from "In-Database Learning with Sparse Tensors" 2016-2018 paper)
page 2: "Semi-ring dictionaries realize the well-known connection between relations and tensors" (from "In-Database Learning with Sparse Tensors" 2016-2018 paper)
no subject
Date: 2023-12-04 09:04 am (UTC)That seems incorrect to me. Multiplication by scalars is obviously commutative.
Since I'm not familiar with technical details of any of this stuff, it's really useless for me to read what chatgpt said. I can spot an error only in a domain where I already know the technical details. In domains where I am just trying to learn new stuff, chatgpt's output will mislead without me noticing.
For example, it says "Yes, this is closely related" and actually it could be unrelated, how do we know? Chatgpt didn't say why they were closely related other than superficially (dictionaries with numeric leaves vs. nested dictionaries with semiring-valued leaves).
no subject
Date: 2023-12-04 04:35 pm (UTC)In this case, I can double check their definition and note that they indeed do consider the generality of non-commutative rings (section 2.1, page 3). So her remark is correct.
(This is, actually, very good, because doing this with rings of matrices might be quite interesting to try.)
The point is, I want to make progress without diving deeply. Later, if diving deeply turns out to be warranted, I would do that.
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Other than that, I know my paper really well, I am trying to get a quick feel whether the techniques from this one are likely to help me make progress with some open problems with my approach. If one does not know either paper, I don't quite see why one would be interested in comparing these two papers. But I have some very particular needs in mind (the main reason why my neural machines are not very practical compared to Transformers is that my machines are not GPU-friendly and not highly optimized in their full generality, so rectifying that is fairly central to me).
no subject
Date: 2023-12-05 10:57 am (UTC)Multiplication is defined in a way that is not commutative by default, where multiplying a dictionary with a scalar results in each value of the dictionary being multiplied by the scalar
This phrase is confusing: it says that multiplication is not commutative by default (what does "default" mean here?) and then it talks about multiplying dictionaries by scalars as if to illustrate the non-commutativity.
To understand what this means, you need to actually look into the paper and find what is commutative and what is non-commutative.
A reasonable rewrite would be: "Multiplication by scalars is in general non-commutative. (full stop, it's going to be a different topic now!) Multiplying a dictionary with a scalar results in ..."
no subject
Date: 2023-12-05 12:50 pm (UTC)(Как и в том, что я пишу, особенно, если я решаю не исправлять, а оставляю, как получилось (это - некоторая особенность текущей парадигмы, что она может думать только вслух, а не про себя; это можно чинить, но до какой степени надо торопиться это чинить, это не очень понятно).)